(2x^2-5x-3)(7x+2)=0

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Solution for (2x^2-5x-3)(7x+2)=0 equation: 


Simplifying
(2x2 + -5x + -3)(7x + 2) = 0

Reorder the terms:
(-3 + -5x + 2x2)(7x + 2) = 0

Reorder the terms:
(-3 + -5x + 2x2)(2 + 7x) = 0

Multiply (-3 + -5x + 2x2) * (2 + 7x)
(-3(2 + 7x) + -5x * (2 + 7x) + 2x2 * (2 + 7x)) = 0
((2 * -3 + 7x * -3) + -5x * (2 + 7x) + 2x2 * (2 + 7x)) = 0
((-6 + -21x) + -5x * (2 + 7x) + 2x2 * (2 + 7x)) = 0
(-6 + -21x + (2 * -5x + 7x * -5x) + 2x2 * (2 + 7x)) = 0
(-6 + -21x + (-10x + -35x2) + 2x2 * (2 + 7x)) = 0
(-6 + -21x + -10x + -35x2 + (2 * 2x2 + 7x * 2x2)) = 0
(-6 + -21x + -10x + -35x2 + (4x2 + 14x3)) = 0

Combine like terms: -21x + -10x = -31x
(-6 + -31x + -35x2 + 4x2 + 14x3) = 0

Combine like terms: -35x2 + 4x2 = -31x2
(-6 + -31x + -31x2 + 14x3) = 0

Solving
-6 + -31x + -31x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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